you need to go two half way from the farthest point from the left to the right so that would be from 2 to 8 which is a distance of 6 so you go halfway over and that puts you at 5 then you find the distance from the lowest point to the highest point which goes from -2 to 6 with a distance of 8 so that means you go up for which puts you at 2 which means the center of the triangle is at the point (5, 2)

## Answers ( )

Answer:(5,2)

Step-by-step explanation:you need to go two half way from the farthest point from the left to the right so that would be from 2 to 8 which is a distance of 6 so you go halfway over and that puts you at 5 then you find the distance from the lowest point to the highest point which goes from -2 to 6 with a distance of 8 so that means you go up for which puts you at 2 which means the center of the triangle is at the point (5, 2)

Answer:Therefore orthocentre is

( 5 , 1.5 )Step-by-step explanation:Fromthegeneralequationofacircle,Substitute K(2, -2), L(4,6), M(8,-2) in (x,y)

K(2, -2):4g – 4f + c = -8

Divideby4:g–f+c=–2(1)L(4,6):4^2 + 6^2 + 2g(4) + 2f(6) + c = 08g + 12f + c = -52

Divideby4:2g+3f+c=–13(2)M(8,-2):8^2 +(-2)^2 + 2g(8) + 2f(-2) + c = 016g – 4f + c = -68

Divideby4:4g–f+c=–17(3)Equation(2)–(1)g + 4f = -11

g = -11 – 4f ———–(a)

Equation(3)–(2)2g – 4f = -4

2g = -4 + 4f ———-(b)

Substituteforgineqn(b)2(-11 – 4f) = -4 + 4f

-12f = 18

f =–1.5Fromeqn(a)g = -11 – 4(-1.5)

g = -5Sincetheorthocentreisgivenby(–g,–f)Thereforeorthocentreis(5,1.5)